Find the least number of 4-digit which is divisible by 18,24and 32.
18=2×3×324=2×2×2×332=2×2×2×2×2LCM of 18,24 and 32=2×2×2×2×2×3×3=288 To get the smallest four-digit number that is divisible by 288, we have to write the multiplies of 288.288×2=576288×3=864288×4=1152
Hence, the least number of 4-digit which is divisible by 18,24and 32 is 1152.