Question

Find the least number of square tiles of equal dimensions required to pave the floor of a room 4.03 m long and 2.17 m broad.

• A. 62
• B. 91
• C. 45
• D. 31

Answer 1

The correct option is B

91

Length of largest square tile = H.C.F. of 403 cm and 217 cm
$403=217\times 1+186,$
$217=186\times 1+31$ and
$186=31\times 6+0.$

$\therefore$ HCF = 31 cm

Area of each tile = $(31\times 31)c{m}^2$

$\text{Required number of tiles}=\frac{\text{Area of the floor}}{\text{Area of one tile}}$
$=\frac{403\times 217}{31\times 31}$
$=91$
Therefore, the required number of tiles is 91.