Question

Find the least number of square tiles required to pave the ceiling of a room $15m17cm$, long and $9m2cm$ broad.

Answer 1

Given,

Length of the room $=15m17cm=(15\times 100)cm+17cm=1517cm$

Breath $=9m2cm=902cm$

The $HCF$ of the $1517$ and $902$ will be the size of square tile.

$1517=41\times 37$

$902=41\times 22$

$HCF$ $1517$ and $902=41cm$

Area of rectangular room $=length\times breath=1517\times 902c{m}^2$

Area of square tiles $=side\times side=41\times 41c{m}^2$

Least number of square tiles required $=\frac{(1517\times 902)}{(41\times 41)}$

$=814$ tiles.

so, $814$ tiles are required to pave the ceiling of the room.