Question

Find the least number that must be added to 1300 so as to get a perfect square.

• A. 67
• B. 69
• C. 71
• D. 68

Answer 1

The correct option is B

69

Applying the long division method we have,

$\begin{array}{cc}& 36\\ 3& 1300\\ & 9\\ 6& 400\\ & 396\\ & 4\end{array}$

From above, it is clear that given number 1300 is greater than $(36{)}^2$
So, we will have to add a minimum number we will add such a number which will make it square of just preceding number, which is 37
i.e., ${36}^2<1300<{37}^2$

i.e., $1296<1300<1369$

1369 - 1300 = 69

The required number is 69.