Question

Find the least number which must be substracted from $6203$ to obtain a perfect square. Also, find square root of the number obtained.

• A. $119,98$
• B. $119,78$
• C. $159,78$
• D. $139,78$

Answer 1

The correct option is B $(119,78)$

Let's find the square root of $6203$ by Long Division method as follows

$\therefore$ 119 is the extra number.

$(78{)}^2<6203<(79{)}^2$

$\therefore 119$ must be subtracted to get a perfect square.

Hence, the least number which should be subtracted to get a perfect square is $119$.

$6203-119=6084$ is the perfect square.

Therefore, the square root of $6084$ is $78$.