Question

Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

• A. 3604
• B. 1015
• C. 1022
• D. 18004

Answer 1

The correct option is D 18004

The L.C.M of 16,20,25,18 is to be 3600.
The required number will be in form of 3600x+4.
Now apply hit and trial method to find the least value of x for which 3600x+4 are divisible by 7.
By putting x = 1, 2, 3 and putting the value of x = 5, the required number comes to be 18004.