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Question

# Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

A
3604
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B
1015
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C
1022
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D
18004
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Solution

## The correct option is D 18004The L.C.M of 16,20,25,18 is to be 3600. The required number will be in form of 3600x+4. Now apply hit and trial method to find the least value of x for which 3600x+4 are divisible by 7. By putting x = 1, 2, 3 and putting the value of x = 5, the required number comes to be 18004.

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