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Question
Find the least number which when divided by 32, 64 & 128 leaves the remainder of 8. (3 marks)
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Solution
The smallest number that is divisible by 32, 64, 128 is the LCM of 32, 64, 128. (1 mark)
LCM of 32, 64, 128 =
= 2×2×2×2×2×2×2
=128 (1 mark)
When 128 is divided by 32, 64 & 128 there is no remainder. So, to get remainder 8 when divided by 32, 64 & 128, 8 is to be added to 128 i.e., 128+8 = 136 (1 mark)
The smallest number that is divisible by 32, 64, 128 is the LCM of 32, 64, 128. (1 mark)
LCM of 32, 64, 128 =
= 2×2×2×2×2×2×2
=128 (1 mark)
When 128 is divided by 32, 64 & 128 there is no remainder. So, to get remainder 8 when divided by 32, 64 & 128, 8 is to be added to 128 i.e., 128+8 = 136 (1 mark)
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