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LCM

Find the leas...

Question

Find the least number which when divided separately by 15, 20, 48 and 36 will leave a remainder 9 in each case

A

1

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B

3

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C

0

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D

6

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Solution

The correct option is B 0
Required number $=$ (L.C.M of $15, 20, 48$ and $36$ ) $+ 9$

$= (2 \times 2 \times 3 \times 5 \times 4 \times 3)$

$= 720 + 9$

$= 729$

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