Find the least positive integer that is divisible by both 2 and 5 and leaves a remainder of 2 when it is divided by 7.
A
20
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B
30
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C
50
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D
65
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E
75
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Solution
The correct option is E30 Let the least positive number be n, given that when n is divided with 7, the remainder is 2. So we get n=7k+2 (where k is integer).
Now we should select least positive value of k such that n must be divisible by 2 and 5. We can observe that k=5 is the least value of k for which n will be divisible by both 2 and 5. Therefore for k=5, we get n=30