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Question

Find the least possible 5 digit number which when divided by 2, 4, 6 and 8, it leaves the remainders 1, 3, 5 and 7 respectively? ___

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Solution

The possible value = (LCM of 2, 4, 6, 8) m - 1
= 24m - 1
Since, the least 5 digit number is 10000. So the required number must be atleast 10000. So putting the value of m = 417, we get (10008 - 1) = 10007, which is the required number.

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