Question

Find the $\left[\frac{7}{9}{p}^{2}qr\right]\times \left(18p{q}^2\right)(-\frac{3}{14}{r}^2)$

Answer 1

$\left[\frac{7}{9}{p}^{2}qr\right]\times \left(18p{q}^2\right)(-\frac{3}{14}{r}^2)=\frac{7}{9}\times 18\times \frac{-3}{14}\times p^{2}qr\times p{q}^2\times r^2=\frac{7\times 18\times -3}{9\times 14}\times p^3\times q^3\times r^3=-3p^3{q}^3{r}^3$