Question

Find the leftmost and the rightmost number when the following numbers are represented on the number line.

$\frac{-19}{10},\frac{-9}{5}\frac{-8}{5}\frac{-3}{2}\frac{-17}{10}$

• A. $\frac{-19}{10}$, $\frac{-3}{2}$
• B. $\frac{-19}{10}$, $\frac{-9}{5}$
• C. $\frac{-3}{2}$, $\frac{-17}{10}$
• D. $\frac{-9}{5}$, $\frac{-17}{10}$

Answer 1

The correct option is A

$\frac{-19}{10}$, $\frac{-3}{2}$

Let us find the decimal values of the given rational numbers and compare them.

$\frac{-19}{10}=-1.9$

$\frac{-9}{5}=-1.8$

$\frac{-8}{5}=-1.6$

$\frac{-3}{2}=-1.5$

$\frac{-17}{10}=-1.7$

So, the ascending order is :
-1.9, -1.8, -1.7, -1.6, -1.5

Hence, the ascending order of the given numbers is :

$\frac{-19}{10},\frac{-9}{5},\frac{-17}{10},\frac{-8}{5},\frac{-3}{2}$

The leftmost and rightmost number on the number line is
$\frac{-19}{10}and\frac{-3}{2}respectively.$