Question

Find the length and perimeter of the rectangle of area $900m^2$ and breadth $20m.$

Answer 1

Step 1 Finding the length of the rectangle:

Given Area = $900m^2$and breadth = $20m.$

Area of rectangle = $l\times b\mathrm{where}\mathrm{l}\mathrm{is}\mathrm{length}\mathrm{and}\mathrm{b}\mathrm{is}\mathrm{the}\mathrm{breadth}$

$$\begin{gathered} 900=l\times 20 \\ l=\frac{900}{20} \\ l=45m \end{gathered}$$

Hence, the length of the rectangle is$45m$

Step 2 Finding the perimeter of the rectangle:

We know that length is $45m$ and breadth is $20m$

The perimeter of the rectangle = $2(l+b)$

$$\begin{gathered} Perimeter=2(45+20) \\ =2\left(65\right) \\ =130m \end{gathered}$$

Hence, the perimeter of the rectangle is $130m$