Question

Find the length( in cm ) of a chord which is at a distance of $8cm$ from the centre of a circle of radius $17cm$.

Answer 1

REF.IMAGE.

AD = 8 cm

AC = AB = 17 cm

$A{C}^2=A{D}^2+D{C}^2$

$DC=\sqrt{(17{)}^2-8^2}=\sqrt{289-64}$

$=\sqrt{225}=15$ cm

BC =2DC $=2\times 15$

=30 cm