Find the length of a nickel wire of area of cross section $3 m m^{2}$ to be used for making resistance of $750 Ω$ $(p_{n i c k l e} = 6.84 \times 10^{- 8} Ω m) .$

32894.7

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33895.6

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43218.6

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33456.1

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Solution

The correct option is A 32894.7
Given,
$A = 3 {m m}^{2}$
$R = 750 Ω$
$ρ_{n i c k e l} = 6.84 \times 10^{- 8} Ω m$
To Find,
$l = ?$
Resistance, $R = \frac{ρ \cdot l}{A}$
$\Rightarrow 750 = \frac{(6.84 \times 10^{- 8}) \cdot l}{3 \times 10^{- 6}}$
$\Rightarrow l = \frac{750 \times 3 \times 10^{- 6}}{6.84 \times 10^{- 8}}$

$\Rightarrow l = 32894.7 m$

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Find the length of a nickel wire of area of cross section 3mm2 to be used for making resistance of 750Ω (pnickle=6.84×10−8Ωm).

The correct option is A 32894.7Given,A=3mm2R=750Ωρnickel=6.84×10−8ΩmTo Find,l=?Resistance, R=ρ⋅lA⇒750=(6.84×10−8)⋅l3×10−6⇒l=750×3×10−66.84×10−8⇒l=32894.7m

Find the length of a nickel wire of area of cross section $3 m m^{2}$ to be used for making resistance of $750 Ω$ $(p_{n i c k l e} = 6.84 \times 10^{- 8} Ω m) .$