Find the length of each side of a rhombus whose diagonals are 24 cm and 10 cm long.

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Solution

In a rhombus, diagonals bisect each other at right angles. And the side will be the hypotenuse.

So, half the diagonals = 12cm & 5cm

$S i d e^{2} = 12^{2} + 5^{2} = 144 + 25 = 169$

$s i d e = \sqrt{169} = 13 c m$

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