In ΔAOD and ΔBOC,∠A=∠B=90∘ (given) AD=BC (given) ∠AOD=∠BOC(vertically opposite angles)
∴△AOD≅△BOC
So, OC=OD (CPCT) Given, CD=8cm.OC+OD=8cmOC+OC=8cm (As,OD=OC)2(OC)=8cmOC=4cm.
In the figure given below, AD and BC are equal and perpendicular to the line segment AB. CD cuts AB at O. Then the relation between OC and OD is
In the figure given below, AD and BC are equal and perpendicular to the same line segment AB. CD cuts AB at O. Then the relation between OC and OD is _____ .