Find the length of sides of a triangle whose vertices are $(1, - 1), (0, 4)$ and $(- 5, 3)$ .

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Solution

Vertices are $(1, - 1), (0, 4)$ and $(- 5, 3)$ .

$A B = \sqrt{(0 - 1)^{2} + (4 + 1)^{2}} = \sqrt{1 + 25} = \sqrt{26}$

$B C = \sqrt{(0 - 5)^{2} + (4 - 3)^{2}} = \sqrt{25 + 1} = \sqrt{26}$

$A C = \sqrt{(1 + 5)^{2} + (- 1 - 3)^{2}} = \sqrt{36 + 16} = \sqrt{52}$

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