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Question

Find the length of sub -normal x29−y24=1 at (3,0)

A
43
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B
23
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C
73
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D
None of these
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Solution

The correct option is A 43
Length of sub-normal
=y1(dydx)(x1,y1)
dydx=4x9y
put this in length of sub-normal equation
=y1(4x19y1)(3,0)
=129=43

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