Find the length of the conductor which is moving at a speed of 10 m/s in the direction perpendicular to the direction of magnetic field of induction 0.6 T, if it induces an emf of 18 V between the ends of the conductor.

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Solution

The correct option is C 3m
Given that B = 0.6 T, v = 10 m/s and ε = 18 V.
Using ε = Blv
18 = 0.6 (l) (10)
l (length of the conductor) = 3m.

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Find the length of the conductor which is moving at a speed of 10 m/s in the direction perpendicular to the direction of magnetic field of induction 0.6 T, if it induces an emf of 18 V between the ends of the conductor.

The correct option is C 3mGiven that B = 0.6 T, v = 10 m/s and ε = 18 V. Using ε = Blv 18 = 0.6 (l) (10) l (length of the conductor) = 3m.

The correct option is C 3m
Given that B = 0.6 T, v = 10 m/s and ε = 18 V.
Using ε = Blv
18 = 0.6 (l) (10)
l (length of the conductor) = 3m.