Question

Find the length of the longest rod can be put in a room with dimensions 10 meters, 8meter, and 6 meters.

Answer 1

Given
The length of the room (l) $=10$ meter breath (b) $=8$ meter height $\left(h\right)=6$ meter
The longest rod that can be put in the room will be equal of its diagonal.
Diagonal $=\sqrt{l^2+b^2+h^2}$
$=\sqrt{{10}^2+8^2+6^2}$
$=\sqrt{200}$
$=10\sqrt{2}m$
$\therefore$ The length of the longest rod $=10\sqrt{2}m$.