Question

Find the length of the longest rod that can be placed in a room 16 m long, 12 m broad and $10\frac{2}{3}$ m high.

• A. 67/3 m
• B. 68/3 m
• C. 23 m
• D. 68 m
• E. 79 m

Answer 1

The correct option is B

68/3 m

Required length =$\sqrt{{\left(16\right)}^2+{\left(12\right)}^2+{\left(\frac{32}{3}\right)}^2}m=\sqrt{256+144+\frac{1024}{9}}m$

$\sqrt{\frac{4624}{9}}m=\frac{68}{3}m=22\frac{2}{3}m$