Find the length of the rectangle whose area and breadth are $40 x^{2}$ $y^{3}$ and $8 x y^{2}$ , respectively.

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Solution

Area of rectangle of length $l$ and breadth $b$ is $l \times b$
Then, $l \times b = 40 x^{2} y^{3}$
$= Length \times 8 x y^{2} = 40 x^{2} y^{3}$
$= Length = 40 x^{2} y^{3} \div 8 x y^{2}$
$= Length = 5 x y$

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