Find the length of the rectangle whose breadth is $10 c m$ and perimeter is $50 c m .$

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Solution

Finding the length of the rectangle:
Given that, perimeter of the rectangle is $50 c m$
We know that, the perimeter of the rectangle $= 2 (l + b)$ , where $l = l e n g t h & b = b r e a d t h$
$\Rightarrow 2 (l + 10) = 50 c m \Rightarrow l + 10 = 25 \Rightarrow l = (25 - 10) c m \Rightarrow l = 15 c m .$
Hence, the length of the rectangle is equal to $15 c m$ .

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