Question

Find the lengths of the medians AD and BE of $△$ ABC whose vertices are A(7, -3), B(5, 3)and C(3, -1).

Answer 1

The given vertices are A(7, -3), B(5, 3) and C(3, -1)

Since D and E are the midpoints of BC and AC respectively, therefore

Coordinates of

D = (5+3)/2,(3–1)/2
=(4,1)

Coordinates of

E = (7+3)/2,(−3−1)/2
=(5,−2)

Now,

AD=√(7–4)2+(−3−1)2
=√9+16=√25=5

BE=√(5–5)2+(3+2)2
=√0+25=√25=5

Hence, AD = BE = 5 units