Find the lengths of the medians of a $△$ ABC having vertices at A (0, -1), B (2, 1) and C (0, 3).

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Solution

D = Midpoint of AB = $left parenthesis fraction numerator 0 plus 2 over denominator 2 end fraction comma fraction numerator negative 1 plus 1 over denominator 2 end fraction right parenthesis equals left parenthesis 1 comma 0 right parenthesis$
E = Midpoint of BC = $left parenthesis fraction numerator 2 plus 0 over denominator 2 end fraction comma fraction numerator 1 plus 3 over denominator 2 end fraction right parenthesis equals left parenthesis 1 comma 2 right parenthesis$
F = Midpoint of CA = $left parenthesis 0 over 2 comma fraction numerator 3 minus 1 over denominator 2 end fraction right parenthesis space equals space left parenthesis 0 comma 1 right parenthesis$

Length of median passing through A = Distance between A and E =
units

Length of median passing through B =
Distance between B and F = units

Length of median passing through C = Distance between C and D
= units

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Find the lengths of the medians of a △ABC having vertices at A (0, -1), B (2, 1) and C (0, 3).

D = Midpoint of AB = E = Midpoint of BC = F = Midpoint of CA = Length of median passing through A = Distance between A and E = units Length of median passing through B = Distance between B and F = units Length of median passing through C = Distance between C and D = units

Find the lengths of the medians of a $△$ ABC having vertices at A (0, -1), B (2, 1) and C (0, 3).