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Question

Find the lengths of the medians of a triangle whose vertices are A (-1, 3) and B (1, -1) and C (5, 1).

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Solution

A (-1,3) B(1,-1) C(5,1)

>Median through A passes through A and midpoint of BC.
Midpoint of BC = left parenthesis fraction numerator 5 plus 1 over denominator 2 end fraction comma fraction numerator 1 minus 1 over denominator 2 end fraction right parenthesis equals left parenthesis 3 comma 0 right parenthesis

Length of Median = square root of left parenthesis 3 plus 1 right parenthesis squared plus left parenthesis 0 minus 3 right parenthesis squared equals end root square root of 4 squared plus 3 squared end root equals square root of 25 equals 5
Length of the median is 5 units.

>Median through B passes through B and midpoint of AC.
Midpoint of AC = (512,1+32)=(2,2)

Length of Median =(21)2+(2+1)2=10
Length of median is 10 units.

>Median through C passes through C and midpoint of AB.
Midpoint of BC = left parenthesis fraction numerator negative 1 plus 1 over denominator 2 end fraction comma fraction numerator 3 minus 1 over denominator 2 end fraction right parenthesis space equals space left parenthesis 0 comma 1 right parenthesis

Length of Median = square root of left parenthesis 5 minus 0 right parenthesis squared plus left parenthesis 1 minus 1 right parenthesis squared end root equals 5
Length of the median is 5 units.


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