Find the lengths of the normals drawn from the point on the axis of the parabola y2=8x whose distance from the focus is 8.
We have,
y2=8x
On comparing that,
y2=4ax
a=2
Then,
We know that,
xt+y=4at+2t3
Then focus is (2,0) and the point on the axis is (10,0).
Then,
10=2t2+4
t2=3
Normal is at the point (6,4√3)
The, required length is
=√(10−6)2+(4√3−0)2
=√42+48
=√64
=8