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Question

Find the like terms from the given terms and add them:
4xyz,2x2y2,3x2y2,4x2,9x2y2,18x2,6xyz,10x2,7xyz

A
(1) 11xyz
(2) 12x2y2
(3) 32x2
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B
(1) 17xyz
(2) 14x2y2
(3) 32x2
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C
(1) -17xyz
(2) 14x2y2
(3) 28x2
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D
none
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Solution

The correct option is B (1) 17xyz
(2) 14x2y2
(3) 32x2
We know that like terms are terms whose variables (and their exponents such as the 2 in x2) are the same.

In the given terms 4xyz,2x2y2,3x2y2,4x2,9x2y2,18x2,6xyz,10x2,7xyz, the like terms are as follows:

(i) 4xyz,6xyz,7xyz

(ii) 2x2y2,3x2y2,9x2y2

(iii) 4x2,18x2,10x2

Now, adding the like terms, we get:

(i) 4xyz+6xyz+7xyz=17xyz

(ii) 2x2y2+3x2y2+9x2y2=14x2y2

(iii) 4x2+18x2+10x2=32x2

Hence, after adding the like terms we get 17xyz,14x2y2,32x2.

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