Find the like terms from the given terms and add them: 4xyz,2x2y2,3x2y2,4x2,9x2y2,18x2,6xyz,10x2,7xyz
A
(1) 11xyz (2) 12x2y2 (3) 32x2
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B
(1) 17xyz (2) 14x2y2 (3) 32x2
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C
(1) -17xyz (2) 14x2y2 (3) 28x2
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D
none
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Solution
The correct option is B(1) 17xyz (2) 14x2y2 (3) 32x2 We know that like terms are terms whose variables (and their exponents such as the 2 in x2) are the same.
In the given terms 4xyz,2x2y2,3x2y2,4x2,9x2y2,18x2,6xyz,10x2,7xyz, the like terms are as follows:
(i) 4xyz,6xyz,7xyz
(ii) 2x2y2,3x2y2,9x2y2
(iii) 4x2,18x2,10x2
Now, adding the like terms, we get:
(i) 4xyz+6xyz+7xyz=17xyz
(ii) 2x2y2+3x2y2+9x2y2=14x2y2
(iii) 4x2+18x2+10x2=32x2
Hence, after adding the like terms we get 17xyz,14x2y2,32x2.