Find the limits of x3-1-x2-1- when x-1-

To find the limits of #160; #160; #160;x^3+1x^2 #160; 1 #160; when #160; #160;x #160;= 1 i.e. #160; lim_x #160;→ 1x^3+1x^2 ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Factorization Method Form to Remove Indeterminate Form

Find the limi...

Question

Find the limits of $\frac{x^{3} + 1}{x^{2} - 1}$ , when $x = - 1$ .

Open in App

Solution

Suggest Corrections

Similar questions

i .

lim x \to 1 [\frac{x^{2} + 1}{x + 100}]

i i .

lim x \to 2 [\frac{x^{3} - 4 x^{2} + 4 x}{x^{2} - 4}]

i i i .

lim x \to 2 [\frac{x^{2} - 4}{x^{3} - 4 x^{2} + 4 x}]

i v .

lim x \to 2 [\frac{x^{3} - 2 x^{2}}{x^{2} - 5 x + 6}]

v .

lim x \to 1 [\frac{x - 2}{x^{2} - x} - \frac{1}{x^{3} - 3 x^{2} + 2 x}]

lim x \to 1 [{(\frac{4}{x^{2} - x^{- 1}} - \frac{1 - 3 x + x^{2}}{1 - x^{2}})}^{- 1} + 3 \frac{x^{4} - 1}{x^{3} - x^{- 1}}] .

\frac{1 - x + log x}{1 - \sqrt{2 x - x^{2}}},

x = 1

\frac{1 - x^{2}}{2 x^{3} - 1} \div \frac{1 - x}{2 x^{2}}

(1)

x = \infty

(2)

x = 0

lim x \to 9 (\frac{3 - \sqrt{x}}{9 - x} + \frac{1}{3 - \sqrt{x}} - 6. \frac{x^{2} + 162}{729 - x^{3}}) .

Join BYJU'S Learning Program