Find the load offered by the cloth :

2.5 g f

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25 k g f

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5 k g f

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2.5 k g f

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Solution

The correct option is D $2.5 k g f$
Effort Arm $= 2 c m$
Load Arm $= 8 c m$
Load $= 10 k g f$
Mechanical advantage $= \frac{Effort Arm}{Load Arm} = \frac{2}{8} = 0.25$
$Load = Mechanical Advantage * effort = 0.25 * 10 = 2.5 k g f$

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A pair of scissors is used to cut a piece of a cloth by keeping it at a distance of 8.0 cm from its rivet and applying an effort of 10 kgf by fingers at a distance of 2.0 cm from the rivet.

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Find the load offered by the cloth :

The correct option is D 2.5kgfEffort Arm =2cmLoad Arm =8cmLoad =10kgfMechanical advantage =Effort ArmLoad Arm=28=0.25Load= Mechanical Advantage ∗ effort=0.25∗10=2.5kgf

The correct option is D $2.5 k g f$
Effort Arm $= 2 c m$
Load Arm $= 8 c m$
Load $= 10 k g f$
Mechanical advantage $= \frac{Effort Arm}{Load Arm} = \frac{2}{8} = 0.25$
$Load = Mechanical Advantage * effort = 0.25 * 10 = 2.5 k g f$