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Coordinates of a Point in Space

Find the locu...

Question

Find the locus of a point which is $5$ units away from Origin.

x^{2} + y^{2} = 25

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x^{2} + y^{2} - 10 x - 10 y + 25 = 0

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2 x^{2} + y^{2} - 5 x - 5 x + 10 = 0

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None.

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Solution

The correct option is A $x^{2} + y^{2} = 25$
Let Locus of point P $(x, y)$

Origin O $(0, 0)$

Geometrical condition $P O = 5 u t .$

$\sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = 5$

$\sqrt{(x_{2} - 0)^{2} + (y_{2} - 0)^{2}} = 5$

$(x)^{2} + y^{2} = 25$

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