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Question

Find the locus of a point which moves in such a way that the sum of its distances from(4,3) and (4,1) is 5.

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Solution

Let the moving or variable point be P(x,y) and the given points be A(4,3) and B(4,1)
By the conditions of the problem,
PA+PB=5
PA=5PB
(x4)2+(y3)2=5(x4)2+(y1)2
(x4)2+(y3)2=25+(x4)2+(y1)210(x4)2+(y1)2
y26y+9=25+y22y+110(x4)2+(y1)2
10(x4)2+(y1)2=4y+17
Squaring both sides again
100(x28x+16+y22y+1)=(4y+17)2
100(x2+y28x2y+17)=16y2+136y+284
100x2+100y216y2800x200y136y+1700284=0
100x2+84y2800x336y+1411=0

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