Find the locus of a variable point which is at a distance of $2$ units from the $y -$ axis

x = \pm 2

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y = \pm 2

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x = \pm 4

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y = \pm 4

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Solution

The correct option is A $x = \pm 2$
Let the variable point be $(h, k)$ then distance from $y$ axis i.e. $x = 0$ is
$2 = ∣ ∣ ∣ \frac{h}{\sqrt{1}} ∣ ∣ ∣ \Rightarrow h = \pm 2$
Hence locus is $x = \pm 2$

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Find the locus of a variable point which is at a distance of 2 units from the y−axis

The correct option is A x=±2Let the variable point be (h,k) then distance from y axis i.e. x=0 is 2=∣∣∣h√1∣∣∣⇒h=±2Hence locus is x=±2

Find the locus of a variable point which is at a distance of $2$ units from the $y -$ axis

The correct option is A $x = \pm 2$
Let the variable point be $(h, k)$ then distance from $y$ axis i.e. $x = 0$ is
$2 = ∣ ∣ ∣ \frac{h}{\sqrt{1}} ∣ ∣ ∣ \Rightarrow h = \pm 2$
Hence locus is $x = \pm 2$