Find the locus of the point which is at a distance of 3 units from the origin.

$x + y + z = 3$

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$x + y + z = 9$

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$x^{2} + y^{2} + z^{2} = 9$

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$x^{2} + y^{2} + z^{2} = 3$

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Solution

The correct option is C
$x^{2} + y^{2} + z^{2} = 9$

Let P(x,y,z) be the required point.
According to the given condition
$\sqrt{(x - 0)^{2} + (y - 0)^{2} + (z - 0)^{2}} = 3 \Rightarrow x^{2} + y^{2} + z^{2} = 9$

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