Question

Find the locus of the point which is at distance of $6units$ from the point $(7,-1)$

Answer 1

Let the locus be $(x,y)$

Distance of $(x,y)$ and $(7,-1)$ is $6$

$⟹(x-7{)}^2+(y+1{)}^2=6^2$

The locus is $x^2+y^2-14x+2y+14=0$