Find the locus of the poles of tangents to $x^{2} / a^{2} + y^{2} / b^{2} = 1$ with respect to the concentric ellipse $c^{2} x^{2} + d^{2} y^{2} = 1$ .

a^{2} c^{4} x^{2} + b^{2} d^{4} y^{2} = 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a^{2} c^{2} x^{2} + b^{2} d^{2} y^{2} = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{2} c^{4} y^{2} + b^{2} d^{4} x^{2} = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $a^{2} c^{4} x^{2} + b^{2} d^{4} y^{2} = 1$

Suggest Corrections

Similar questions

c^{2} x^{2} + d^{2} y^{2} = 1

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1,

c^{2} x^{2} + d^{2} y^{2} = 1

x^{2} + y^{2} = d^{2}

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

\frac{x^{2}}{α^{2}} + \frac{y^{2}}{β^{2}} = 1

\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

\frac{x^{2}}{a^{4}} + \frac{y^{2}}{b^{4}} = \frac{1}{c}

c

Join BYJU'S Learning Program