Question

Find the locus point which is $5$ units apart from $(2,3)$

Answer 1

Given point is $(2,3)$

Let the required point be $(x,y)$

It is $5$ units apart from $(2,3)$

$\sqrt{(x-2{)}^2+(y-3{)}^2}=5(x-2{)}^2+(y-3{)}^2=25x^2-4x+4+y^2-6y+9=25x^2+y^2-4x-6y-12=0$