Question

Find the lowest 4-digit number which when divided by 3 , 4 or 5 leaves a remainder of 2 in each case?

• A. $1022$
• B. $2300$
• C. $3044$
• D. $1111$

Answer 1

The correct option is A $1022$

Lowest 4 digit number $=1000$

$LCM(3,4and5)=3\times 4\times 5$

$=60$

$\frac{1000}{60}=16\times 60+40$

First 4 digit number divisible by $60=16\times 60+60$$=1020$

So, the required number$=1020+2$$=1022$