Question

Find the magnetic field at a point which is at $2\text{m}$ on perpendicular bisector of finite current carrying wire of length $6\text{m}$. If the current of $10\text{A}$ is flowing as shown in the figure, then which of the following options is the correct magnetic field at that point.

• A. $0.6\mu \text{T}⨀$
• B. $0.6\mu \text{T}⨂$
• C. $6\mu \text{T}⨀$
• D. $6\mu \text{T}⨂$

Answer 1

The correct option is A $0.6\mu \text{T}⨀$

Magnetic field due to a current carrying finite wire of length $a$ at a point $d$ on the perpendicular bisector is given by $$B=\frac{{\mu }_{0}ia}{2\pi d\sqrt{{\left(a\right)}^2+{\left(4d\right)}^2}}$$From the data given in the question,

$B=\frac{4\pi \times {10}^{-7}\times 10\times 6}{2\pi \times 2\times \sqrt{{\left(6\right)}^2+{(4\times 2)}^2}}$

$\Rightarrow B=0.6\mu \text{T}$

Hence, option (a) is the correct answer.