Find the magnitude of acceleration (in m/s2) of the system if all surfaces are smooth. g=10m/s2.
A
2
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B
3
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C
4
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D
6
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Solution
The correct option is B 3 Acceleration of the blocks are shown in the FBD
So, from the FBDs we have T2−4g.sin30∘=4a.........(i) 5g−T1=5a...................(ii)
On solving (i) & (ii) we have T2−T1+3g=9a............(iii)
Now, from the FBD of 1Kg mass T1−T2=a...........(iv)
From eq (iii) & (iv) we have, 3g=10a⟹a=3010=3m/s2
Alternate:
Supporting force = 5g=5×10=50N
Opposing force = 4g.sin30∘=2g=20N
Magnitude of acceleration of the system is given by, a=Supporting Force - Opposing ForceTotal mass =5g−2g10=3m/s2