Find the magnitude of angle A, if
2 sin A cos A - cos A -2 sin A + 1 = 0
0° , 30°
Given that 2 sin A cos A - cos A -2 sin A + 1 = 0
Taking cos A common , we have
cos A ( 2 sin A -1 ) - 1( sin A - ) = 0
(cos A - 1 ) ( 2 sin A - 1) = 0
Hence ( cos A - 1) = 0 and ( 2 sin A -1 ) = 0
∴ cos A = 1 and 2 sin A = 1 ; sin A = 12
A = 0° and A = 30 ° ( ∵ Cos 0° = 1 and sin 30 ° = 12)