Find the magnitude of the average emf induced in the loop during its removal.

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Solution

No. of turns $= 50$ ,
Area of square $= 0.25 m^{2}$
Magnitude of magnetic field $= 1$ T
Average rate of complete removal $= Δ s / Δ t = 1 m / s^{2}$
$∴$ average induced emf $= N G \frac{Δ S}{Δ t} = 50$ volt.

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Find the magnitude of the average emf induced in the loop during its removal.

No. of turns =50,Area of square =0.25m2Magnitude of magnetic field =1TAverage rate of complete removal =Δs/Δt=1m/s2∴ average induced emf =NGΔSΔt=50 volt.

No. of turns $= 50$ ,
Area of square $= 0.25 m^{2}$
Magnitude of magnetic field $= 1$ T
Average rate of complete removal $= Δ s / Δ t = 1 m / s^{2}$
$∴$ average induced emf $= N G \frac{Δ S}{Δ t} = 50$ volt.