Find the magnitude of the gravitational force acting on a particle of mass $2$ kg placed at the origin.

26

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

30

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

35

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $26$ N
$\to F = {\to E}_{m} = (10^i + 24^j) N$
$= \sqrt{(100) + 576} = 26 N$

Suggest Corrections

Similar questions

Q. The gravitational field in a region is given by

_{g}

= 5^i + 12^j

N/Kg, then the magnitude of the gravitational force acting on a particle of mass 2 Kg. placed at the origin, will be:

Q. Forces of magnitude 20 N,

10 \sqrt{3}

20 \sqrt{3}

N and 10 N respectively are acting on a particle of mass 2 kg due east, due north, due south and due west. Find acceleration of the particle.

The gravitational potential in a region is given by $V = 20 N k g^{- 1}$ (x + Y). (a) show that the equation is dimensionally correct. (b) Find the gravitational field at the point (x,y), Leave your answer in terms of the unit vectors $\to i, \to j, \to K .$ N $k g^{- 1}$ (c) Calculate the magnitude of the gravitational force on a particle of mass 500 g placed at the origin.

The magnitude of force needed to produce an acceleration of 4 $m s^{- 2}$ in a ball of mass 6 kg is

Q. A particle of mass

50 g

experience a gravitational force

2.0

N when placed at a particular point. Then the magnitude of gravitational field at that point is

K \times 10

N/kg. Then the value of K is______(K is an integer)

Join BYJU'S Learning Program

Find the magnitude of the gravitational force acting on a particle of mass 2kg placed at the origin.

The correct option is A 26N→F=→Em=(10^i+24^j)N=√(100)+576=26 N

Find the magnitude of the gravitational force acting on a particle of mass $2$ kg placed at the origin.

The correct option is A $26$ N
$\to F = {\to E}_{m} = (10^i + 24^j) N$
$= \sqrt{(100) + 576} = 26 N$