The given vectors a → and b → have same magnitude, that is, | a → |=| b → |, θ= 60 0 and a → ⋅ b → = 1 2 .
Formula used for dot product is,
a → ⋅ b → =| a → || b → |cosθ
Here, the angle between a → and b → is θ.
Substitute the values in the above formula.
1 2 =| a → || a → |×cos 60 0 1 2 = | a → | 2 × 1 2 | a → | 2 =1 | a → |=±1
The magnitude of vector is always positive so,
| a → |=1
Thus, the magnitude of vector a → and b → is 1.