Find the mass defect of the $Helium - 4$ nucleus.

Given mass of the helium nucleus $M_{He} = 4.0015084 u$
Mass of a proton $m_{p} = 1.007276 u$
Mass of a neutron $m_{n} = 1.008665 u$

0.30374 u

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0.030374 u

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0.030384 u

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0.03074 u

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Solution

The correct option is B $0.030374 u$
Mass defect,
$Δ m = (Z m_{p} + (A - Z) m_{n}) - M_{He}$

For helium, $_{2} {He}^{4}$ , $Z = 2; A = 4$

$\Rightarrow Δ m = (2 \times 1.007276 u) + (2 \times 1.008665 u) - 4.0015084 u$

$\Rightarrow Δ m = (2.014552 u + 2.017330 u) - 4.0015084 u$

$\Rightarrow Δ m = 4.031882 u - 4.0015084 u$

$\Rightarrow \begin{matrix} Δ m = 0.030374 u \end{matrix}$

Hence, option $(B)$ is correct.

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