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Molecular Mass

Find the mass...

Question

Find the mass of $29.12 L$ of $S O_{3}$ gas at STP.

A

83.2 g

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B

63.9 g

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C

28.4 g

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D

104 g

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Solution

The correct option is D $104 g$
1 mole of $S O_{3}$ occupies 22.4 L at STP.
$29.12 L$ will be occupied by $\frac{1}{22.4} \times 29.12 = 1.3$ moles of $S O_{3}$
$Mass of S O_{3} = number of moles \times molar mass = 1.3 \times 80 = 104 g$

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