f(x)= x 0<x<1 xER
f '(x)=1
As f '(x) cannot be equal to 0 max and min value of f(x) does not exist if x is a real no.
conversely by looking at function we can see that min value of f(x)-->0 when x-->0 & cannot be predicted
Similarly max value of f(x)-->1 when x-->1 & cannot be predicted
if f(x) was defined in [0,1],min value=0,max value=1