Find the maximum acceleration of a block which is oscillating with frequency 2 Hz and amplitude 50 cm.

$78.8 m / s^{2}$

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100 m / s^{2}

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50 m / s^{2}

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40 m / s^{2}

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Solution

The correct option is A
$78.8 m / s^{2}$

The acceleration of the block under oscillation is given by
$a = ω^{2} x$
a will be max when x is max, i.e. at A

$a_{m a x} = ω^{2} A = 4 π^{2} f^{2} A$

$= 4 \times 9.86 \times 4 \times 0.5 = 78.8 m / s^{2}$

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Find the maximum acceleration of a block which is oscillating with frequency 2 Hz and amplitude 50 cm.

The correct option is A 78.8m/s2 The acceleration of the block under oscillation is given by a=ω2x a will be max when x is max, i.e. at A amax=ω2A=4π2f2A =4×9.86×4×0.5=78.8m/s2

The correct option is A
$78.8 m / s^{2}$

The acceleration of the block under oscillation is given by
$a = ω^{2} x$
a will be max when x is max, i.e. at A

$a_{m a x} = ω^{2} A = 4 π^{2} f^{2} A$

$= 4 \times 9.86 \times 4 \times 0.5 = 78.8 m / s^{2}$